Construct a triangle ABC in which BC = 5 cm, \angle B = 60^{\circ} and AC + AB = 7.5 cm.

Answers (1)

Given : BC = 5 cm, \angle B = 60^{\circ} , AC + AB = 7.5 cm

            Steps of Construction:

            1.         Draw a line BC = 5 cm

            2.         Draw an angle of 60^{\circ} at B

            3.         Mark an arc on line of angle 60° with radius 7.5 cm at point D.

            4.         Join DC

            5.         Bisect DC which intersects BD at point A

            6.         Join AC

            DABC is the required triangle.

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