# Construct a triangle ABC in which BC = 5 cm, $\angle B = 60^{\circ}$ and AC + AB = 7.5 cm.

Given : BC = 5 cm, $\angle B = 60^{\circ}$ , AC + AB = 7.5 cm

Steps of Construction:

1.         Draw a line BC = 5 cm

2.         Draw an angle of $60^{\circ}$ at B

3.         Mark an arc on line of angle 60° with radius 7.5 cm at point D.

4.         Join DC

5.         Bisect DC which intersects BD at point A

6.         Join AC

DABC is the required triangle.

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