Construct the following and give justification :
A rhombus whose diagonals are 4 cm and 6 cm in lengths.
Given : Rhombus with diagonals length = 4 cm, 6 cm
Steps of Construction :
1. Draw a line AB = 4 cm
2. Bisect the AB using another line EF which intersects it at point X
E X F is perpendicular to AB
3. As center X mark an arc of 3 cm as the radius on XF and XE which intersects at C and D respectively.
4. Join AD, AE, BC, BD
ACBD is the required rhombus.
Justification :
hence DA = DB, AC = BC …..(1)
{every point on perpendicular bisector of line is equidistance from end points of line}
Also, XD = XC = 3 cm
Thus, AB is perpendicular to DC
BD = BC …..(2)
From 1 and 2, ABCD is a rhombus.