Construct the following and give justification :
A triangle if its perimeter is 10.4 cm and two angles are and .
Steps of Construction :
3. Bisect and and then let their bisectors meet at point A
4. Bisect line AQ and AP which meets PQ at C and B respectively.
5. Join A with B and C.
ABC is the required triangle.
Justification:
Since B and C lies on PQ
Hence, PB + BC + CQ = AB + BC + AC = PQ
…..(i) { in DAPB, AB = PB}
[ is an exterior angle of DAPB]
{from (i),}
Also, [in DAQC ; AC = CQ]
[ is exterior angle of DAQC]
[\AQ is a bisector of ]