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Construct the following and give justification :

A triangle PQR given that QR = 3cm, \angle PQR=45^{\circ} and QP – PR = 2 cm.

Answers (3)

Given : QR = 3cm, \angle PQR=45^{\circ} , QP – PR = 2 cm.

            

            Steps of Construction :

            1.         Draw line QR = 3 cm

            2.         Draw line QB with 45^{\circ} angle at Q.

            3.         Make an arc on QB of 2cm radius intersecting at A

            4.         Join AR

            5.         Bisect AR and extend it so it intersects QB at P

            6.         Join PR

            PQR is the required triangle.                         

           

            Justification:

            P lies on perpendicular bisector of AB.

            Hence, PA = PQ

            QA = PQ – PA           

            QA = PQ – PR           \left (\because PA = PR \right )

 

Posted by

infoexpert21

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B

Posted by

naveenkumar130301

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PA=PR

Posted by

Suryaprakash

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