# Construct a triangle whose sides are 3.6 cm, 3.0 cm and 4.8 cm. Bisect the smallest angle and measure each part.

Steps of Construction :

1.         Draw a line AB = 4.8 cm

2.         With A as center, mark an arc of 3.6 cm radius and with B as center, cut the arc with 3 cm radius at point C.

3.         Draw the line AC and BC which are of length 3.6 cm and 3 cm respectively.

4.         With A as center, draw an arc which cuts AB and AC at point F, E respectively.

5.         With E and F as center, draw arcs which intersect at G.

6.         Draw line AD which passes through G,

D is mid-point of BC.

A is the smallest angles because the angle in front of the smallest side is the smallest.

$\angle CAB =38^{\circ}, \angle ABC = 50^{\circ}, \angle ACB =92^{\circ}$

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