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  • Draw the effective equivalent circuit of the circuit shown in Fig 7.1, at extremely high frequencies and find the effective impedance.

Draw the effective equivalent circuit of the circuit shown in Fig 7.1, at extremely high frequencies and find the effective impedance.


 

Answers (1)

Explanation:-

so, now finding the Inductive reactance

X_L=\omega L=2\pi fL

At very high frequencies,

X_L will be high or L can be considered an open circuit for the high frequency of AC circuit.
Capacitive reactance

X_C=\frac{1}{2\pi \nu C} 

 Therefore reactance of capacitance can be considered negligible and the capacitor can be considered short-circuited. 

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infoexpert21

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