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  • Study the circuits (a) and (b) shown in Fig 7.2 and answer the following questions. (a) Under which conditions would the rms currents in the two circuits be the same?(b) Can the rms current in circuit (b) be larger than that in (a)?

Study the circuits (a) and (b) shown in Fig 7.2 and answer the following questions.

(a) Under which conditions would the rms currents in the two circuits be the same?
(b) Can the rms current in circuit (b) be larger than that in (a)?

Answers (1)

I_{rms} \: in (a)=\frac{V_{rms}}{R}
\\I_{rms} in (b)=\frac{V_{rms}}{\sqrt{R^2+(X_L-X_C )}}\\\\ \\(a)Now (I_{rms} )_a=(I_{rms} )_b\\\\ \frac{V_{rms}}{R}=\frac{V_{rms}}{\sqrt{R^2+(X_L-X_C )^2}}\\\\ \\R=\sqrt{R^2+(X_L-X_C )}

Squaring both sides
\\R^2=R^2+\left ( X_L-X_C \right )^{2}\\\\ Or \left ( X_L-X_C \right )^{2}=0\\ \\X_L=X_C
So, I_{rms} in circuits a and b will be equal if \\ \\X_L=X_C

(b)\: \: For (I_{rms} )_b>(I_{rms })_a

\\\frac{V_{rms}}{\sqrt{R^2+(X_L-X_C )}}>\frac{V_{rms}}{R}\\ \\ As V_{rms=V} \\\\So\: \: \sqrt{R^2+(X_L-X_C )}<R \\ \\ Squaring\: \: both \: \: sides R^2+(X_L-X_C )^2<R^2

(X_L-X_C )^2<0

Square of a number can'tbe negative. 

Therefore, the rms current in circuit (b) has to be larger than that in (a).

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infoexpert21

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