Get Answers to all your Questions

header-bg qa

Draw the effective equivalent circuit of the circuit shown in Fig 7.1, at extremely high frequencies and find the effective impedance.


 

Answers (1)

Inductive reactance

X_L=\omega L=2\pi fL

At very high frequencies, X_L will be high or L can be considered an open circuit for the high frequency of ac circuit.
Capacitive reactance

X_C=\frac{1}{2\pi \nu C} 

At high frequency, X_Cwill below.

 Therefore reactance of capacitance can be considered negligible and capacitor can be considered short-circuited. 

Posted by

infoexpert21

View full answer