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  • The output of a step-down transformer is measured to be 24 V when connected to a 12-watt light bulb. The value of the peak current is

The output of a step-down transformer is measured to be 24 V when connected to a 12-watt light bulb. The value of the peak current is
\\A.\: 1/\sqrt{2}A\\ B.\: \sqrt{2}A\\ C. \: 2A\\ D.\:2\sqrt{2}A
 

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\\ V_s=24 V P_s=12 W\\I_s V_s=12\\I_s=\frac{12}{V_s} =\frac{12}{24}=0.5 \: ampere\\ I_0=I_s \sqrt{2}=0.5\sqrt{2}=\frac{1}{\sqrt{2} }\: ampere

 

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