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  • Figure 10.1 shows a ray of light as it travels from medium A to medium B. Refractive index of the medium B relative to medium A is (a) √3 /√ 2 (b) √2 / √3 (c) 1/ √2 (d) 2

Figure 10.1 shows a ray of light as it travels from medium A to medium B. The Refractive index of medium B relative to medium A is

(a) \sqrt{3}/\sqrt{2}

(b) \sqrt{2}/\sqrt{3}

(c) {1}/\sqrt{2}

(d) \sqrt{2}

Answers (1)

Hence, the correct answer is option (a).

Explanation:-

the refractive index of medium r relative to medium i, we use Snell's Law:

nisin?θi = nrsin?θr

Here:

  • ni and nr? are the refractive indices of medium i and medium r, respectively,
  • θi? = 45? (angle of incidence in medium i),
  • θr = 30 (angle of refraction in medium r).

The refractive index of B with respect to A =\frac{\sin\; i}{\sin\; r}

=\frac{\sin\; 60^{o}}{\sin\; 45^{o}}

=\frac{\sqrt{3}}{\sqrt{2}}

Posted by

infoexpert23

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