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  • Find P(0), P(1), P(–2) for the following polynomials: i. P(x)=10x-4x^{2}-3 ii. P(y)=\left ( y+2 \right )\left ( y-2 \right )

Find P(0), P(1), P(–2) for the following polynomials:

i. P(x)=10x-4x^{2}-3

ii. P(y)=\left ( y+2 \right )\left ( y-2 \right )

Answers (1)

(i)  P(0) = –3; P(1) = 3; P(–2) = –39

Solution: Given polynomial is P(x) = 10x – 4x2 – 3

Put x = 0,

P(0) = 10(0) – 4(0) – 3

       = 0 – 0 – 3

      = – 3

Put x = 1,

P(1) = 10(1) – 4(1)2 – 3

       = 10 – 4 – 3

       = 10 – 7

       = 3

Put x = –2,

P(–2) = 10(–2) –4(–2)2 – 3

          = – 20 – 16 – 3

          = – 39

Hence, P(0) = –3; P(1) = 3; P(–2) = –39

(ii)

P(0) = – 4; P(1) = – 3; P(–2) = 0

Solution.

Given polynomial is P(y) = (y + 2) (y – 2)

Put y = 0,

P(0)= (0 + 2) (0 – 2)

       = (2) (–2)

       = – 4

Put y = 1,

P(1) = (1 + 2) (1 – 2)

        = (3) (–1)

        = – 3

Put y = – 2,

P(–2) = (–2 + 2) (–2 – 2)

          = (0) (–4)

          = 0

Hence, P(0) = – 4; P(1) = – 3; P(–2) = 0.

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