Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the mean deviation about the mean of the distribution:Size:20 frequency:6

Find the mean deviation about the mean of the distribution:

Size 20 21 22 23 24
Frequency 6 4 5 1 4



 

Answers (2)

We have to find the mean deviation about the mean of the distribution in this question.

 Let us make a table of the given data and fill up the other columns after calculations

Size (x_{i})

Frequency  (f_{i})

f_{i}x_{i}

20

6

120

21

4

84

22

5

110

23

1

23

24

4

96

Total

20

433

Here, mean  \bar{x} = \frac{\sum f_{i}x_{i}}{\sum f_{i}} = \frac{433}{20} = 21.65

So the above table can be rewritten as

Size (x_{i})

Frequency  (f_{i})

f_{i}x_{i}

d_{i} = \left |x_{i} -\bar{x} |

f_{i}d_{i}

20

6

120

1.65

9.90

21

4

84

0.65

2.60

22

5

110

0.35

1.75

23

1

23

1.35

1.35

24

4

96

2.35

9.40

Total

20

433

6.35

25.00

     Hence, mean deviation becomes = \frac{\sum f_{i}x_{i}}{\sum f_{i}} = \frac{25}{20} = 1.25

 

Posted by

infoexpert21

View full answer
Posted by

infoexpert21

View full answer

Similar Questions

Latest Question