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  • Standard deviations for first 10 natural numbers is A. 5.5 B. 3.87 C. 2.97 D. 2.87

Standard deviations for first 10 natural numbers is
A. 5.5
B. 3.87
C. 2.97
D. 2.87

Answers (1)

\\ \text{We know that the standard deviation of the first n natural numbers is }\sqrt {\frac{n^{2}-1}{12}}~ \\ \\ \text{Now for first 10 natural numbers} n=10 \\ \\ \text{ substituting this in the equation of standard deviation we get }\sigma =\sqrt {\frac{ \left( 10 \right) ^{2}-1}{12}}=\sqrt {\frac{100-1}{12}}= \sqrt {\frac{99}{12}}= \sqrt {8.25} =2.87 \\

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