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The mean deviation of the data 3, 10, 10, 4, 7, 10, 5 from the mean is
A. 2
B. 2.57
C. 3
D. 3.75

Answers (1)

Given data is 3,10, 10, 4, 7 ,10 ,5 . They are total 7.

\\ \text{Here mean, }\overline{X~}=\frac{3+10+10+4+7+10+5}{7}=\frac{49}{7}=7 \\\\ \text{ This can be written in table form as,} \\\\

\begin{array}{|l|l|} \hline \text { Data }\left(x_{i}\right) & \multicolumn{1}{|c|} {d_{i}=\left|x_{i}-\bar{x}\right|} \\ \hline 3 & 4 \\ \hline 10 & 3 \\ \hline 10 & 3 \\ \hline 4 & 3 \\ \hline 7 & 0 \\ \hline 10 & 3 \\ \hline 5 & 2 \\ \hline \text { Total } & =18 \\ \hline \end{array}

\\ \text{Hence Mean Deviation becomes,} M.D=\frac{ \Sigma d_{i}}{7}=\frac{18}{7}=2.57 \\\\

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