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  • If a linear equation has solutions (–2, 2), (0, 0) and (2, – 2), then it is of the form

If a linear equation has solutions (–2, 2), (0, 0) and (2, – 2), then it is of the form

(A) y – x = 0

(B) x + y = 0

(C) –2x + y = 0

(D) –x + 2y = 0

Answers (1)

Answer:

(B) x + y = 0

Solution:

(A) Put the given points in y – x = 0

Putting (–2, 2)            

LHS     = 2 – (–2)

= 2 + 2

 = 4\neq 0 (RHS)

The given equation does not satisfy this point, so there is no need to check for other points.

(B) Now put the given points in x + y = 0

Putting (–2, 2)            

LHS     = –2 + 2 = 0 (RHS)

Putting (0, 0)              

LHS    = 0 + 0 = 0 (RHS)

Putting (2, –2)            

LHS     = 2 – 2 = 0 (RHS)

The given equation is satisfying all the points

(C) Put the given points in –2x + y = 0

Putting (–2, 2)            

LHS     = (–2) (–2) + (2)

= 4 + 2 = 6 \neq 0 (RHS)

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