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Determine the point on the graph of the linear equation 2x + 5y = 19, whose ordinate is 1\frac{1}{2}  times its abscissa.

Answers (1)

Answer:

(2, 3)

Solution:

The given linear equation is 2x + 5y = 19 … (i)

Here it is given that the ordinate is \frac{3}2  times its abscissa

y=\frac{3}2x  ... (1)

Put the value of y in above equation (i) we get

2x +5\left ( \frac{3}{2} x\right )=19

2x +\frac{15x}{2}=19

\frac{4x +15x}{2}=19

19 x = 19 \times 2

x = \frac{19 \times 2}{19}=2

x = 2

Put the value of x in equation (i)

y=\frac{3}{2}\times 2

y = 3

Hence the point is (2, 3)

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