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  • The graph of the linear equation y = x passes through the point

The graph of the linear equation y = x passes through the point

(A) \left (\frac{3}{2}, -\frac{3}{2} \right )

(B) \left (0, \frac{3}{2} \right )

(C) (1, 1)

(D) \left (\frac{1}{2}, -\frac{1}{2} \right )

Answers (1)

Answer:

(C) (1, 1)

Solution:

The given linear equation is y = x

i.e., y – x = 0

First point is \left (\frac{3}{2}, -\frac{3}{2} \right )

Putting the value of x=\frac{3}{2} in the above equation we get

y-\frac{3}{}2=0

y=\frac{3}{2}

We get y=\frac{3}{2}  which does not satisfy our y-coordinate

Second point is \left (0, \frac{3}{2} \right )  

Putting the value of x = 0 in the given equation, we get

y = 0

We get y = 0 which does not satisfy our y-coordinate

Third point is (1, 1)

Putting the value of x = 1 in the given equation we get

y – 1 = 0

y = 1

We get y = 1 which satisfies our y-coordinate

Fourth point is \left (\frac{1}{2}, -\frac{1}{2} \right )  

Putting the value of x=\frac{1}{2}  in the given equation we get

y-\left (-\frac{1}{2} \right )=0

y=-\frac{1}{2}

We get y=-\frac{1}{2}  which does not satisfy our y-coordinate

Hence only one point which is (1, 1) satisfies the given linear equation.

Therefore option (C) is correct.

Posted by

infoexpert21

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