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x = 5, y = 2 is a solution of the linear equation

(A) x + 2 y = 7

(B) 5x + 2y = 7

(C) x + y = 7

(D) 5 x + y = 7

Answers (2)

Answer:

(C) x + y = 7

Solution:

(A) Putting x = 5, y = 2 in x + 2y = 7 we get

LHS = 5 + 2 (2)

= 5 + 4

= 9 \neq 7 (RHS)

(B) Putting x = 5, y = 2 in 5x + 2y = 7 we get

LHS = 5(5) + 2(2)

= 25 + 4

= 29 \neq 7 (RHS)

(C) Putting x = 5, y = 2 in x + y = 7 we get

LHS = 5 + 2

= 7 = 7 (RHS)

(D) Putting x = 5, y = 2 in 5x + y = 7 we get

LHS = 5(5) + 2

= 25 + 2

= 27 \neq 7 (RHS)

Hence only x + y = 7 satisfies the given values of x and y

Therefore option (C) is correct.

Posted by

infoexpert21

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Answer:

(C) x + y = 7

Solution:

(A) Putting x = 5, y = 2 in x + 2y = 7 we get

LHS = 5 + 2 (2)

= 5 + 4

= 9 \neq 7 (RHS)

(B) Putting x = 5, y = 2 in 5x + 2y = 7 we get

LHS = 5(5) + 2(2)

= 25 + 4

= 29 \neq 7 (RHS)

(C) Putting x = 5, y = 2 in x + y = 7 we get

LHS = 5 + 2

= 7 = 7 (RHS)

(D) Putting x = 5, y = 2 in 5x + y = 7 we get

LHS = 5(5) + 2

= 25 + 2

= 27 \neq 7 (RHS)

Hence only x + y = 7 satisfies the given values of x and y

Therefore option (C) is correct.

Posted by

infoexpert21

View full answer