If AB is a chord of a circle with centre O, AOC is a diameter and AT is the tangent at A as shown in Figure. Prove that BAT =
ACB.
Here [ AC is a diameter line,
Angle in semi-circle formed, is
]
In ABC
[ sum of interior angles of a triangle is
]
......(I)
We know that the diameter of a circle is perpendicular to the tangent.
Equate equation (i) and (ii) we get
Hence Proved