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In Figure, AB and CD are common tangents to two circles of unequal radii. Prove that AB = CD.

Answers (1)

To Prove : AB = CD
Extend AB and CD then they meet at point E.

Here EA = EC     (\because  length of tangent drawn from same point is equal)
Also EB = ED       (\because  length of tangent drawn from some point is equal)
AB = AE - BE
From equal axiom if equal are subtracted from equal then the result is equal.

\therefore AB= CD

Hence Proved


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