Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • In series LCR circuit, the plot of I_{max} v s \omega is shown in Fig 7.3. Find the bandwidth and mark in the figure.

 In a series LCR circuit, the plot of I_{max} v s \: \omega is shown in Fig 7.3. Find the bandwidth and mark in the figure.

Answers (1)

Explanation:-

The bandwidth of the series LCR circuit is defined as the difference between the frequencies at which the impedance (or voltage) drops to its maximum value (the peak value at resonance

I=\frac{E_0}{\sqrt{2}}= \frac{1}{\sqrt{2}}= 0.707\: Amp
From the graph we get

\omega _1=0.8\frac{rad}{s}\: and\:\omega _2=1.2\frac{rad}{s}
Bandwidth =1.2-0.8=0.4\: rad/sec

Posted by

infoexpert21

View full answer

Similar Questions

Latest Question