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  • In series LCR circuit, the plot of I_{max} v s \omega is shown in Fig 7.3. Find the bandwidth and mark in the figure.

 In series LCR circuit, the plot of I_{max} v s \: \omega is shown in Fig 7.3. Find the bandwidth and mark in the figure.

Answers (1)

I=\frac{E_0}{\sqrt{2}}= \frac{1}{\sqrt{2}}= 0.707\: Amp
From graph we get

\omega _1=0.8\frac{rad}{s}\: and\:\omega _2=1.2\frac{rad}{s}
Bandwidth =1.2-0.8=0.4\: rad/sec

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infoexpert21

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