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  • Match the following reactants in Column I with the corresponding reaction products in Column II. Column I (i) Benzene + Cl_2

Match the following reactants in Column I with the corresponding reaction products in Column II.

Column I Column II
(i) Benzene + Cl_{2}\overset{AlCl_{3}}{\rightarrow} (a) Benzoic acid
(ii) Benzene + CH_{3}Cl\overset{AlCl_{3}}{\rightarrow} (b) Methyl phenyl ketone
(iii) Benzene + CH_{3}COCl\overset{AlCl_{3}}{\rightarrow} (c) Toluene
(iv) Toluene \overset{KMnO_{4}/NaOH}{\rightarrow} (d) Chlorobenzene
  (e) Benzene hexachloride

 

Answers (1)

(i) \rightarrow(d); (ii) \rightarrow (c); (iii) \rightarrow (b); (iv) \rightarrow (a)

Explanation:

Friedel-Crafts alkylation is a reaction that replaces a hydrogen atom on an aromatic ring with an alkyl group. It's a type of electrophilic aromatic substitution that uses a Lewis acid catalyst, like aluminum chloride (AlCl3) or iron trichloride (FeCl3), to form a carbocation. The carbocation then attacks the aromatic ring, breaking a double bond and forming an intermediate. The intermediate is deprotonated, which restores aromaticity to the ring and forms an acid that regenerates the Lewis acid catalyst.

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