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Which of the following are correct?

(i)  CH_{3}-O-CH_{2}^{+} is more stable than CH_{3}-CH_{2}^{+}

(ii) \left (CH_{3} \right )_{2}CH^{+} less table than CH_{3}-CH_{2}-CH_{2}^{+}

(iii) CH_{2}=CH-CH_{2}^{+} is more stable than CH_{3}-CH_{2}-CH_{2}^{+}

(iv) CH_{2}=CH^{+} is more stable than CH_{3}-CH_{2}^{+}

Answers (1)

The answer is the option (i)CH_{3}-O-CH_{2}^{+} is more stable than CH_{3}-CH_{2}^{+} & (iii) CH_{2}=CH-CH_{2}^{+} is more stable than CH_{3}-CH_{2}-CH_{2}^{+}.

Explanation: (i)CH_{3}-O-CH_{2}^{+}is more stable than CH_{3}-CH_{2}^{+} because +R effect of CH_{3}-O is greater than -CH_{3} (stability of carbocation increases due to the +R effect).

(iii) We know that the resonance effect is stronger than +I effect. Here, CH_{2}=CH-CH_{2}^{+} \leftrightarrow ^+CH_{3}-CH=CH_{2} is stabilised by resonance effect; whereas CH_{3}-CH_{2}-CH_{2}^{+} is stabilised by +I effect only . Hence, CH_{2}=CH-CH_{2}^{+} is more stable than CH_{3}-CH_{2}-CH_{2}^{+}.

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