Get Answers to all your Questions

header-bg qa

Arrange the following carbanions in order of their decreasing stability.

(i) A > B > C
(ii) B > A > C
(iii) C > B > A
(iv) C > A > B

Answers (1)

The answer is the option (ii) B > A > C

Explanation: CH3 group has +I effect, which decreases the stability of carbon anion and in C this effect direct to negatively charged carbon. +I effect is also present in A, but there is more distant from negatively charged carbon, and in B there is no +I effect

Posted by

infoexpert24

View full answer