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  • Seawater at frequency v = 4 108 Hz has permittivity varepsilon =80 varepsilon _{0}, permeability mu = mu _{0} and resistivity rho =0.25 Omega m.

Seawater at frequency v = 4 x 108 Hz has permittivity \varepsilon =80\; \varepsilon _{0},, permeability \mu =\mu _{0} and resistivity \rho =0.25\; \Omega m.. Imagine a parallel plate capacitor immersed in seawater and driven by an alternating voltage source V(t)=V_{0}\; \sin (2\pi vt). What fraction of the conduction current density is the displacement current density?

Answers (1)

The separation between the plates of the capacitor is

 V(t)=V_{0}\; \sin (2\pi vt)

Ohm’s law for the conduction of current density

J_{0c}=\frac{v}{\rho d}

The displacement current density is

J_{0d}=\frac{2\pi v\varepsilon V_{0}}{d}

The fraction of the conduction of current density and the displacement density

=\frac{J_{0}d}{J_{0}c}=\frac{4}{9}

Posted by

infoexpert23

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