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Show that the radiation pressure exerted by an EM wave of intensity I on a surface kept in vacuum is \frac{I}{c}.

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Energy received by the surface per second, E = IA

No.of photons received per second by the surface

=N=\frac{E}{E_{photon}}=\frac{E\lambda }{hc}=\frac{IA\lambda }{hc}

For a perfectly absorbing surface, is

\Delta P=\frac{h}{\lambda }

Force

, F=N.\Delta P=\left ( \frac{IA\lambda }{hc} \right )\left ( \frac{h}{\lambda } \right )=\left ( \frac{IA}{c} \right )

Pressure,

P=\frac{F}{A}=\frac{I}{c}

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