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  • The charge on a parallel plate capacitor varies as q = q 0 cos2 pi vt The plates are very large and close together. Neglecting the edge effects. find the displacement current through the capacitor?

The charge on a parallel plate capacitor varies as q = q_0 \cos 2 \pi vt. The plates are very large and close together. Neglecting the edge effects, find the displacement current through the capacitor?

Answers (1)

Here, the value of displacement current through the capacitor is Id

Therefore,

I_d = I_c = \frac{dq}{dt}.......a)

Given,

q = q_0 \cos 2 \pi vt

Substituting the values in the equation a), we get

I_d = I_c = \left ( \frac{dq}{dt} \right )\left ( q_0 \cos 2 \pi vt \right )= -2 \pi v \;q_0 \sin2 \pi vt

Posted by

infoexpert21

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