The initial state of a certain gas is P_i, V_i, T_i. It undergoes expansion till its volume becomes V_f. Consider the following two cases:

a) the expansion takes place at constant temperature

b) the expansion takes place at constant pressure

Plot the P-V diagram for each case. In which of the two cases, is the work done by the gas more?

Answers (1)

 

The expansion from Vto Vf at a constant temperature in (a) is an isothermal expansion.i.e.
P_{i}V_{i}=P_fV_f  at a constant temp.

The expansion at constant pressure in (b) is the isobaric process wherein the graph of P-V will be parallel to V axis until its volume becomes V_f.

The area enclosed by graph (a) is less than the graph (b). So, work done by the process (b) is more than (a).

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