Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • The magnetic field of a beam emerging from a filter facing a floodlight is given by B_0 = 12 \times 10^{-8} \sin (1.20 \times 10^{7} z - 3.60 \times 10^{15} t)T. What is the average intensity of the beam

The magnetic field of a beam emerging from a filter facing a floodlight is given by B_0 = 12 \times 10^{-8} \sin (1.20 \times 10^{7} z - 3.60 \times 10^{15} t)T. What is the average intensity of the beam?

Answers (1)

Here, given equation,

B_0 = 12 \times 10^{-8} \sin (1.20 \times 10^{7} z - 3.60 \times 10^{15} t)T.

Standard equation,

B_0 = 12 \times 10^{-8 } \;T

By comparing the given equation with the standard equation, we get:

I_{av} = \frac{1}{2}\;\left ( \frac{B_0^{2}}{u_0} \right )c = 1.71 \; \;19 \;wb/m^{2}

 

Posted by

infoexpert21

View full answer

Similar Questions

Latest Question