Get Answers to all your Questions

header-bg qa

The product of three consecutive positive integers is divisible by 6”. Is this statement true or false? Justify your answer

Answers (1)

best_answer

The given statement is true in all the conditions.
  Let three consecutive positive integers be, x, x + 1 and x + 2.
Divisibility by 3: Whenever a number is divided by 3, the remainder obtained is either 0 or 1 or 2.
\thereforen = 3p or 3p + 1 or 3p + 2, where p is some integer.
So, we can say that one of the numbers among x, x + 1 and x + 2 is always divisible by 3.

\Rightarrow x (x + 1) (x + 2) is divisible by 3.
Divisibility by 2: Whenever a number is divided 2, the remainder obtained is 0 or 1.
\thereforen = 2q or 2q + 1, where q is some integer.
So, we can say that one of the numbers among x, x + 1 and x + 2 is always divisible by 2.
\Rightarrowx (x + 1) (x + 2) is divisible by 2.
Since, x (x + 1) (x + 2) is divisible by 2 and 3.
   \therefore x (x + 1) (x + 2) is divisible by 6.

Posted by

infoexpert27

View full answer