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If two positive integers a and b are written as a = x3 y2 and b = xy3; x, y are prime numbers then HCF (a, b)
  (A) xy              (B) xy2             (C) x3y3                      (D) x2y2
 

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 a= x^{3}y^{2}\Rightarrow x\times x\times x\times y\times y
 b= xy^{3}\Rightarrow x\times y\times y\times y
For HCF, we have to take all common prime numbers from both the numbers.
Hence,
\text{HCF = }x\times y\times y= xy^{2}
\text{ HCF =}xy^{2}

Hence option B is correct.

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