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  • The zeroes of the quadratic polynomial x^2 + 99x + 127 are (A) both positive

The zeroes of the quadratic polynomial x^2 + 99x + 127 are

(A) both positive

(B) both negative

(C) one positive and one negative

(D) both equal

Answers (1)

Answer. [B]

Solution. Polynomial : It is an expression of more than two algebraic terms, especially the sum of several terms that contains different powers of the same variable(s) and a quadratic polynomial is polynomial of degree 2.

Here the given quadratic polynomial is x^2 + 99x + 127

x^2 + 99x + 127

a = 1, b = 99, c = 127

x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

x=\frac{-99\pm \sqrt{(99)^{2}-4(1)(127)}}{2(1)}

x=\frac{-99\pm \sqrt{9801-508}}{2(1)}

x=\frac{-99\pm \sqrt{9293}}{2}

x=\frac{-99\pm 96.4}{2}

x=\frac{-99+ 96.4}{2}                                                            x=\frac{-99-96.4}{2}

x=\frac{-2.6}{2}=-1.3                                                          x = -97.7

The value of both the zeroes are negative.

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infoexpert21

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