Two circles with centres O and O' of radii 3 cm and 4 cm, respectively intersect at two points P and Q such that OP and O'P are tangents to the two circles. Find the length of the common chord PQ.
Answer
4.8 cm
Solution
Given : Radii of two circles are OP = 3 cm and and intersection point of two circles are P and Q. Here two tangents drawn at point P are OP and P
Also apply Pythagoras theorem in we get
Equate equation (i) and (ii) we get
Put x = 1.8 in equation (i) we get