Which of the following equation depicts reducing nature of H_2O_2 ?

(i) \;2\left [ Fe(CN) _{6}\right ]^{4-}+2H^{+} + H_{2}O_{2}\rightarrow 2\left [Fe \left ( CN \right )_{ 6}\right ]^{3-}+2H_{2}O

(ii)I_{2}+H_{2}O_{2}+2OH^{-}\rightarrow 2I^{-}+2H_{2}O+O_{2}

(iii)Mn^{2+}+H_{2}O_{2}\rightarrow Mn^{4+}+2OH^{-}

(iv)PbS+4H_{2}O_{2}\rightarrow PbSO_{4}+4H_{2}O

 

Answers (1)

The answer is the option (ii)I_{2}+H_{2}O_{2}+2OH^{-}\rightarrow 2I^{-}+2H_{2}O+O_{2}

Iodine in the form of I_{2} is reduced to I^{-} and thus H_2O_2 acts as the reducing agent.

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