A coordination compound CrCl_{3}.4H_{2}O precipitates silver chloride when treated with silver nitrate. The molar conductance of its solution corresponds to a total of two ions. Write the structural formula of the compound and name it.

Name: A coordination compound CrCl_{3}.4H_{2}O precipitates silver chloride when treated with silver nitrate. The molar conductance of its solution corresponds to a total of two ions. Write the structural formula of the compound and name it.
Uploaded: Thu, 2020-11-26 14:31
Description: A coordination compound CrCl_{3}.4H_{2}O precipitates silver chloride when treated with silver nitrate. The molar conductance of its solution corresponds to a total of two ions. Write the structural formula of the compound and name it.

#Coordination compounds
#Chemistry
#NCERT
#Exemplar Chemistry for Class 12

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#8.1
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A coordination compound $CrCl_{3}.4H_{2}O$ precipitates silver chloride when treated with silver nitrate. The molar conductance of its solution corresponds to a total of two ions. Write the structural formula of the compound and name it.

Answers (1)

There should be one free chlorine atom left outside the coordination sphere if silver chloride is formed in the reaction. $\left [ Cr\left ( H_{2}O \right )_{4}Cl_{2} \right ]Cl$ has to be the formula and it is called tetraaquadichlorido chromium(III) chloride.

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A coordination compound precipitates silver chloride when treated with silver nitrate. The molar conductance of its solution corresponds to a total of two ions. Write the structural formula of the compound and name it.

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A coordination compound $CrCl_{3}.4H_{2}O$ precipitates silver chloride when treated with silver nitrate. The molar conductance of its solution corresponds to a total of two ions. Write the structural formula of the compound and name it.