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In the following question match the items given in Columns I and II.

Match the compounds given in Column I with the oxidation state of cobalt present in it (given in Column II) and assign the correct code.

Column I (Compound) Column II (Oxidation state of Co)
A. \left [ Co\left ( NCS \right )\left ( NH_{3} \right )_5 \right ]\left ( SO_{3} \right ) 1. +4
B. \left [ Co\left ( NH_{3} \right )_{4}Cl_{2} \right ] SO_{4} 2. 0
C. Na_{4}\left [ Co(S_{2}O_{3}) _{3}\right ] 3. +1
D. [Co_{2}(CO)_{8}] 4. +2
                              5. +3

(i) A (1) B (2) C (4) D (5)

(ii) A (4) B (3) C (2) D (1)

(iii) A (5) B (1) C (4) D (2)

(iv) A (4) B (1) C (2) D (3)

Answers (1)

Option (iii) is the correct answer.

Explanation: The oxidation state of the whole molecule is considered to calculate the oxidation state of CMI (central metal ion).

(a) \left [ Co\left ( NCS \right )\left ( NH_{3} \right )_5 \right ]\left ( SO_{3} \right )

Let oxidation state of Co be x.

                      x-1+5\times 0=+2

                         x=+2+1=+3

(b) \left [ Co\left ( NH_{3} \right )_{4}Cl_{2} \right ] SO_{4}

Let oxidation state of Co = x.

\Rightarrow x+4\times0+2\times(-1)=+2

                                     x-2=+2

                                               x=4

(c) Na_{4}\left [ Co(S_{2}O_{3}) _{3}\right ]

Let oxidation state of Co = x.

                       x+3\times(-2)=-4

                                    x-6=-4

                       x=-4+6=+2

(d) [Co_{2}(CO)_{8}]

Let oxidation state of Co = x.

                   x-8\times 0=0

                                    x=0

Hence, correct choice is (d)

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