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A cyclist starts from centre O of a circular park of radius 1km and moves along the path OPRQO as shown in Fig. 4.3. If he maintains a constant speed of 10 ms–1, what is his acceleration at point R in magnitude and direction?

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To calculate acceleration in a circular motion, we have a formula.

A=\frac{v^{2}}{R}

Given, R=1000 \; m, v = 10\; m/s

Hence, A=10\times \frac{10}{1000}=\frac{1}{10}=0.1\; m/s^{2}

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