Given that a shopkeeper has:

Volume of sphere $=\frac{4}{3}\pi R^{3}$                           (where R is the radius)

Volume of 1 larger laddoo $=\frac{4}{3}\pi \left ( 5 \right )^{3}$

Volume of 1 smaller laddoo $=\frac{4}{3}\pi \left ( 2.5 \right )^{3}$

Volume of 1 larger laddoo = Total volume of all smaller laddoos formed

Let number of smaller laddoos be n.

Volume of n smaller laddoo $=n\left ( \frac{4}{3}\pi \left ( 2.5 \right )^{3} \right )$

So,

$\Rightarrow \frac{4}{3}\pi \times 5^{3}=n\times\frac{4}{3}\pi \times \left ( 2.5 \right )^{3}$

$\Rightarrow 125=n \times \left ( \frac{25}{10} \right )^{3}$

$\Rightarrow n=8 \; laddoos$

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