A shopkeeper has one spherical laddoo of radius 5cm. With the same amount of material, how many laddoos of radius 2.5 cm can be made?

Answers (1)

Answer : 8 laddoos

Given that a shopkeeper has:

Larger laddoo with radius = 5 cm

Smaller laddoo with radius = 2.5 cm

Volume of sphere =\frac{4}{3}\pi R^{3}                           (where R is the radius)

Volume of 1 larger laddoo =\frac{4}{3}\pi \left ( 5 \right )^{3}

Volume of 1 smaller laddoo =\frac{4}{3}\pi \left ( 2.5 \right )^{3}

Volume of 1 larger laddoo = Total volume of all smaller laddoos formed

Let number of smaller laddoos be n.

Volume of n smaller laddoo =n\left ( \frac{4}{3}\pi \left ( 2.5 \right )^{3} \right )

So,

\Rightarrow \frac{4}{3}\pi \times 5^{3}=n\times\frac{4}{3}\pi \times \left ( 2.5 \right )^{3}

\Rightarrow 125=n \times \left ( \frac{25}{10} \right )^{3}

\Rightarrow n=8 \; laddoos

Hence 8 smaller laddoos can be formed by the larger laddoo.

Preparation Products

Knockout NEET May 2021 (One Month)

An exhaustive E-learning program for the complete preparation of NEET..

₹ 14000/- ₹ 6999/-
Buy Now
Foundation 2021 Class 10th Maths

Master Maths with "Foundation course for class 10th" -AI Enabled Personalized Coaching -200+ Video lectures -Chapter-wise tests.

₹ 350/- ₹ 112/-
Buy Now
Knockout JEE Main April 2021 (One Month)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 14000/- ₹ 6999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Boost your Preparation for JEE Main with our Foundation Course
 
Exams
Articles
Questions