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  • The length of the longest pole that can be put in a room of dimensions ( 10 m x 10 m x 5 m ) is (A) 15 m (B) 16 m (C) 10 m (D) 12 m

The length of the longest pole that can be put in a room of dimensions \left ( 10\; m\times\; 10\; m \times 5\; m \right ) is

(A) 15\; m

(B) 16\; m

(C) 10\; m

(D) 12\; m

Answers (1)

Answer (A)

Dimensions of room =10\; m \times \; 10\; m\; \times 5\; m

We can see that the room is in form of a cuboid.

Longest side of a cuboid is its diagonal.

So, we can say that the longest pole will be faced along its diagonal.

Diagonal of cuboid =\sqrt{l^{2}+b^{2}+h^{2}}

=\sqrt{10^{2}+10^{2}+5^{2}}

=\sqrt{225}

=15\; m

So, option (A) is the correct answer.

 

Posted by

infoexpert23

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