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  • Find the amount of water displaced by a solid spherical ball of diameter 4.2 cm, when it is completely immersed in water.

Find the amount of water displaced by a solid spherical ball of diameter 4.2 cm, when it is completely immersed in water.

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Answer: 38.808\; cm^{3}

Given that a solid spherical ball of diameter (d) 4.2 cm is completely immersed in water.

Radius of ball=\frac{d}{2}

                      =\frac{4.2}{2}=2.1\; cm

Now we know that,

Volume of spherical ball =\frac{4}{3}\pi r^{3}                             (where r is the radius)

                                       =\frac{4}{3} \times \pi \times \left ( 2.1 \right )^{3}

                                       =\frac{4}{3} \times \pi \times \left ( 9.261 \right )

                                        =\frac{4}{3} \times \frac{22}{7} \times 9.261

                                        =38.808\; cm^{3}

 Hence volume of spherical ball=38.808\; cm^{3}

Amount of water displaced is same as the volume of spherical ball.

So we have Amount of water displaced =38.808\; cm^{3}

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