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Direction: Write True or False and justify your answer in each of the following :

If the radius of a cylinder is doubled and height is halved, the volume will be doubled.

 

Answers (5)

Answer: True

The given statement is: If the radius of a cylinder is doubled and height is halved, the volume will be doubled.

We know that the volume of cylinder is given as \pi r^{2}h

where the radius of cylinder is r and height is h.

Let original volume be,

V_{1}=\pi r^{2}h

Now the radius of a cylinder is doubled and height is halved,

So,

New Radius (R) = 2r

New Height (H)=\frac{h}{2}

Then, new Volume of cylinder

V_{2}=\pi \left ( 2r \right )^{2}\frac{h}{2}

V_{2}=2\pi r^{2}h=2 \times V_{1}

Hence, the given statement is true.

 

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infoexpert23

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Answer: True

The given statement is: If the radius of a cylinder is doubled and height is halved, the volume will be doubled.

We know that the volume of cylinder is given as \pi r^{2}h

where the radius of cylinder is r and height is h.

Let original volume be,

V_{1}=\pi r^{2}h

Now the radius of a cylinder is doubled and height is halved,

So,

New Radius (R) = 2r

New Height (H)=\frac{h}{2}

Then, new Volume of cylinder

V_{2}=\pi \left ( 2r \right )^{2}\frac{h}{2}

V_{2}=2\pi r^{2}h=2 \times V_{1}

Hence, the given statement is true.

 

Posted by

infoexpert23

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Answer: True

The given statement is: If the radius of a cylinder is doubled and height is halved, the volume will be doubled.

We know that the volume of cylinder is given as \pi r^{2}h

where the radius of cylinder is r and height is h.

Let original volume be,

V_{1}=\pi r^{2}h

Now the radius of a cylinder is doubled and height is halved,

So,

New Radius (R) = 2r

New Height (H)=\frac{h}{2}

Then, new Volume of cylinder

V_{2}=\pi \left ( 2r \right )^{2}\frac{h}{2}

V_{2}=2\pi r^{2}h=2 \times V_{1}

Hence, the given statement is true.

 

Posted by

infoexpert23

View full answer

Answer: True

The given statement is: If the radius of a cylinder is doubled and height is halved, the volume will be doubled.

We know that the volume of cylinder is given as \pi r^{2}h

where the radius of cylinder is r and height is h.

Let original volume be,

V_{1}=\pi r^{2}h

Now the radius of a cylinder is doubled and height is halved,

So,

New Radius (R) = 2r

New Height (H)=\frac{h}{2}

Then, new Volume of cylinder

V_{2}=\pi \left ( 2r \right )^{2}\frac{h}{2}

V_{2}=2\pi r^{2}h=2 \times V_{1}

Hence, the given statement is true.

 

Posted by

infoexpert23

View full answer

Answer: True

The given statement is: If the radius of a cylinder is doubled and height is halved, the volume will be doubled.

We know that the volume of cylinder is given as \pi r^{2}h

where the radius of cylinder is r and height is h.

Let original volume be,

V_{1}=\pi r^{2}h

Now the radius of a cylinder is doubled and height is halved,

So,

New Radius (R) = 2r

New Height (H)=\frac{h}{2}

Then, new Volume of cylinder

V_{2}=\pi \left ( 2r \right )^{2}\frac{h}{2}

V_{2}=2\pi r^{2}h=2 \times V_{1}

Hence, the given statement is true.

 

Posted by

infoexpert23

View full answer