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A small village, having a population of 5000, requires 75 litres of water per head per day. The village has got an overhead tank of measurement 40\; m \times 25\; m \times 15\; m. For how many days will the water of this tank last?

 

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Answer : 40 days

Given, dimension of overhead tank =40\; m \times 25 \; m \times 15\; m

Now the tank is in the shape of a cuboid, so we have volume =l\; b\; h

\Rightarrow Volume of tank =40\; m \times 25 \; m \times 15\; m=15000\; m^{3}

Population of village =5000

Daily water requirement for 1 person = 75 litre

Then daily water requirement for 5000 people =75 \times 5000=375000\; l

Now we know that 1 litre =0.001\; m^{3}

So, daily water requirement for 5000 people =375000 \times 0.001\; m^{3}=375\; m^{3}

Number of Days till the water in this tank will last

=\frac{\text {Volume of tank}}{\text {daily water requirement for 5000 people}}

=\frac{15000\; m^{3}}{375\; m^{3}}=40

Hence, the water of this tank will last for 40 days.

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