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  • In a cylinder, radius is doubled and height is halved, curved surface area will be (A) halved (B) doubled (C) same (D) four times

In a cylinder, if the radius is doubled and height is halved, curved surface area will be

(A) halved

(B) doubled

(C) same

(D) four times

Answers (1)

Answer (C)

We know that the curved surface area of a cylinder is 2\pi r h

(Where r is radius and h is height.)

Let, original radius =r

Original height = h

Original curved surface area \left ( C_{1} \right )=2 \pi r h

Now it is given that radius is doubled and height is halved

New radius (R)=2r

New height (H) =\frac{h}{2}

So, new curved surface area \left ( C_{2} \right )=2 \pi RH

Now, C_{2} =2 \pi RH

C_{2} =2\pi \left ( 2r \right )\times \frac{h}{2}

       =2 \pi rh

 C_{2}=2 \pi rh

then

C_{2}=C_{1}

So, option (C) is the correct answer.

 

Posted by

infoexpert23

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