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  • A system goes from P to Q by two different paths in the P V diagram as shown in Figure Heat given to the system in path 1 is 1000 J The work done by the system along path 1 is more than path 2 by 100 J

A system goes from P to Q by two different paths in the P-V diagram as shown in Figure. Heat given to the system in path 1 is 1000 J. The work done by the system along path 1 is more than path 2 by 100 J. What is the heat exchanged by the system in path 2?

Answers (1)

Step 1: Calculate the change in internal energy.

Given,
Q1=1000J

W1=Work done through path 1

W2=Work done through path 2

W1−W2=100J

Change in internal energy, ΔU=0 (It is not a path function)


Step 2: Calculate values from the first law of thermodynamics.

From the First law of thermodynamics,

For path 1

ΔQ1=ΔU1+ΔW1 ...(i)

For path 2

ΔQ2=ΔU2+ΔW2 ...(ii)


Subtracting from (i) to (ii)

ΔQ1−ΔQ2=ΔW1−ΔW2 (Internal energy is same for both the paths)

1000 J−ΔQ2=100 J

ΔQ2=900 J

Final answer: 900 J.

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