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  • An X-OR gate has following truth table: It is represented by following logic relation Y=bar{A}.B+A.bar{B} Build this gate using AND, OR and NOT gates.

 An X-OR gate has following truth table:

A B Y
0 0 0
0 1 1
1 0 1
1 1 0

It is represented by following logic relation
Y=\bar{A}.B+A.\bar{B}
Build this gate using AND, OR and NOT gates.

Answers (1)

XOR can be obtained by combining two NOT gates, two AND gates and one OR gate. The logic relation for the given table is as follows:

Y=\bar{A}.B+A.\bar{B}=Y_{1}+Y_{2}\\ when\: \: Y_{1}=\bar{A}.B \: \: and\: \: Y_{2}=A.\bar{B}

Y1 cna be obtained as output of AND gate I for which one input is of A through NOT gate and another input is of B. Y2 can be obtained as output of AND gate II for  which one input is of A and other input id of B through NOT gate.

Now Y can be obtained as output from OR where Y1 and Y2 are inputs of OR gate

Thus the logic circuit of this relation is given below

Posted by

infoexpert24

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