Bisectors of the angles B and C of an isosceles triangle ABC with AB = AC intersect each other at O. Show that the external angle adjacent to ABC is equal to
BOC
Given, that ABC is an isosceles triangle
and, AB = AC
To prove: External angle adjacent to ABC is equal to
BOC
Proof: Produce line CB to D in ABC
AB = AC (Given)
ACB =
ABC (angles opposite to equal sides are equal)
OCB =
OBC (Bisector of angle B and C, respectively)
In BOC,
OBC +
OCB +
BOC = 180°
2
OBC +
BOC = 180° (From above)
ABC +
BOC = 180°
(
ABO +
OBC =
ABC)
ABC+
OBA = 180°
OBA =
BOC.
Hence proved.