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  • Consider a heat engine as shown on the figure. Q_1 and Q_2 are heat added to heat bath T_1 and heat taken from T_2 in one cycle of the engine. W is the mechanical work done on the engine.

Consider a heat engine as shown on the figure. Q_{1} and Q_{2} are heat added to heat bath T_{1} and heat taken from T_{2} in one cycle of the engine. W is the mechanical work done on the engine.

If W > 0, then possibilities are:

a) Q_{1} > Q_{2} > 0

b) Q_{2} > Q_{1} > 0

c) Q_{2} < Q_{1} < 0

d) Q_{1} < 0, Q_{2} > 0

Answers (1)

The answer is the option (a) and (c)

Q_{1}=W+Q_{2} (From above figure)
W>0\\ Q_{1}-Q_{2}>0\\ Q_{1}>0

Thus,  Q_{1}>0 if both Q_{1} and Q_{2} are positive.

And Q_{1}<Q_{2}<0 if both are negative.

Hence, a and c are correct.

 

Posted by

infoexpert24

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