Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Consider a heat engine as shown on the figure. Q_1 and Q_2 are heat added to heat bath T_1 and heat taken from T_2 in one cycle of the engine. W is the mechanical work done on the engine.

Consider a heat engine as shown in the figure. Q_{1} and Q_{2} are heat added to the heat bath T_{1} and heat taken from T_{2} in one cycle of the engine. W is the mechanical work done on the engine.

If W > 0, then possibilities are:

a) Q_{1} > Q_{2} > 0

b) Q_{2} > Q_{1} > 0

c) Q_{2} < Q_{1} < 0

d) Q_{1} < 0, Q_{2} > 0

Answers (1)

The correct option is C Q1>Q2>0
Step 1: Recognize the working principle of the system from the given fig.

Formula Used: W=Q1−Q2

The given figure represents the working of a refrigerator

Q1=Q2+W

Therefore,
W=Q1−Q2

Step 2: If W>0

Now,
if, W>0, then

Q1−Q2>0

Q1>Q2>0 ....(i)

If Q2 is negative, Q1 is also negative (but less negative as W>0)
∴Q2<Q1<0 ...(ii)

Final Answer: (a),(c).

Posted by

infoexpert24

View full answer

Similar Questions

Latest Question