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  • D is a point on the side BC of a \triangleABC such that AD bisects \angleBAC. Then (A) BD = CD(B) BA > BD(C) BD > BA(D) CD > CA

D is a point on the side BC of a △ABC such that AD bisects
∠BAC. Then
(A) BD=CD
(B) BA>BD
(C) BD>BA
(D) CD>CA

Answers (1)

Solution.

BC is the side of △ABC, and D is the point on the side of BC.

 In △ABC,∠BAD=∠CAD (Given that AD bisects BAC) In △ADC,∠BDA>∠BAD(∵ Exterior angle of triangle is greater than interior opposite angle) ∠BAD=∠CAD Then BA>BD(∵ Side opposite to greater angle is longer) 

Hence option (A) is correct.

Posted by

infoexpert24

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