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Fig. 1.10 represents a crystal unit of cesium chloride, CsCl. The cesium atoms, represented by open circles are situated at the corners of a cube of side 0.40nm, whereas a Cl atom is situated at the center of the cube. The Cs atoms are deficient in one electron while the Cl atom carries an excess electron.

(i) What is the net electric field on the Cl atom due to eight Cs atoms?
(ii) Suppose that the Cs atom at corner A is missing. What is the net force now on the Cl atom due to the seven remaining Cs atoms?

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Explanation:-

a) As the chlorine atoms are distributed equally from all the eight corners of the cube from the center, Due to symmetry, the electric field contributions from the eight Cs atoms at the corners will add up vectorially. This is because the electric fields due to each of the eight Cs atoms are symmetric about the center, and their magnitudes are the same, but the directions of the fields point in opposite directions, canceling each other out. Since the cube is symmetric, the net electric field at the center (due to the eight charges) will be zero

b) The electric field will be directed toward the missing Cs atom (corner A) because the charge on the Cs atom is positive, and the Cl atom has a negative charge. Therefore, the force on the Cl atom will be directed toward corner A.T he net vector sum of the electric field due the charge A is E_A + E_{seven \: \: charges} = 0

 

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