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If \oint _{s} Eds =0over a surface, then


A. The electric field inside the surface and on it is zero.
B. The electric field inside the surface is necessarily uniform.
C. The number of flux lines entering the surface must be equal to the number of flux lines leaving it
D. All charge must necessarily be outside the surface.

Answers (1)

The correct answers are the options (c,d)

Explanation:  \phi _{s}= 0 represents that number is electric field lines entering an area is equal to the number of electric field lines leaving. And also, here q=0; therefore the charge must be outside the enclosed area.

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